Skip to content

Possible issue. #2

Description

@DmytroHubernatorov

f = open('{}{}.txt'.format(workflow_name, i), 'w')

In case of intensive usage it will not guarantee file name will be 'engaged' by another process.
There are functions for unique file name creation.
Or update implementation like - try to create file name and grab it.

Metadata

Metadata

Assignees

No one assigned

    Labels

    No labels
    No labels

    Type

    No type

    Projects

    No projects

      Milestone

      No milestone

      Relationships

      None yet

      Development

      No branches or pull requests

      Issue actions